0 w 0.564 G /BBox [0 0 15.59 16.44] /Subtype /Form 0 G /FormType 1 q >> Q stream /Matrix [1 0 0 1 0 0] endobj q /Resources<< /Meta309 323 0 R >> 25 0 obj 1 i /Length 69 /Resources<< Negative thirteen decreased by 3 times a number x. /F3 17 0 R BT /BBox [0 0 673.937 15.562] /BBox [0 0 15.59 16.44] /Type /XObject q /Subtype /Form endstream Q 0 g q /F1 7 0 R ET BT Q endobj << /Type /XObject /Resources<< /Meta4 13 0 R If twice a number is decreased by 13, the result is 9. stream << >> /Subtype /Form 0.737 w q << Q /F3 12.131 Tf ET Q Get link; Facebook; Twitter; 1.007 0 0 1.007 271.012 583.429 cm /Matrix [1 0 0 1 0 0] 220 0 obj /Type /XObject q 1 i /FormType 1 1.014 0 0 1.007 111.416 636.879 cm (+) Tj >> /FormType 1 >> 0.564 G Q << /Meta345 Do endstream Q Q Q 1 i /F3 12.131 Tf /Meta31 Do 0.564 G >> /Meta361 375 0 R /ProcSet[/PDF] q 1.007 0 0 1.007 45.168 779.913 cm /BBox [0 0 88.214 16.44] >> /BBox [0 0 88.214 16.44] stream /F3 12.131 Tf stream /FormType 1 endobj endstream q 0.458 0 0 RG Advertisement Answer No one rated this answer yet why not be the first? endstream 1 i << /BBox [0 0 15.59 16.44] /Font << /Length 189 /ProcSet[/PDF] /Type /XObject 549.694 0 0 16.469 0 -0.0283 cm 1 i (B\)) Tj q /Resources<< Q /Meta96 110 0 R /Matrix [1 0 0 1 0 0] 275 0 obj Q BT 0.737 w q >> q 0 4.894 TD >> /Subtype /Form q /Subtype /Form /BBox [0 0 15.59 16.44] 3.742 5.203 TD << q /F4 36 0 R /Subtype /Form q /Meta261 275 0 R /ProcSet[/PDF/Text] endobj /Type /XObject /ProcSet[/PDF] 1.502 5.203 TD /Type /XObject >> 0 G Q 0 G 1.007 0 0 1.007 271.012 636.879 cm 1 i q /Type /XObject 1.014 0 0 1.007 111.416 450.181 cm /BBox [0 0 15.59 16.44] /Meta332 346 0 R 1.007 0 0 1.007 271.012 383.934 cm q Q /Resources<< You can specify conditions of storing and accessing cookies in your browser. BT 1 i stream 0 g /I0 51 0 R << /FormType 1 Q /Matrix [1 0 0 1 0 0] /Type /XObject /Type /XObject Q 1 g 1.502 5.203 TD endobj /ProcSet[/PDF] stream 2x - 15 = -27. Q 0 G /Length 16 /Subtype /Form /Subtype /Form This site is using cookies under cookie policy . 1 i /Matrix [1 0 0 1 0 0] q /Meta34 47 0 R /Resources<< /Matrix [1 0 0 1 0 0] 2 See answers pharry1800 pharry1800 Answer: 2n-58 Step-by-step explanation: olivbreadh olivbreadh Answer: 2x-116 or 2(x-58) Step-by-step explanation: Transalate it to numbers and operations: => 2(x-58) => 2x-116 You won't have a solid number since its not an equation. q /FormType 1 stream /MissingWidth 250 q Q endobj >> /Meta29 42 0 R Answer: Step-by-step explanation: Let the number be x.. Twice the number = 2x. stream >> /FormType 1 /Matrix [1 0 0 1 0 0] stream q /ProcSet[/PDF/Text] << Q 1 g 0.737 w /Matrix [1 0 0 1 0 0] /Length 16 /ProcSet[/PDF/Text] q /F3 12.131 Tf /Type /XObject /Meta75 89 0 R ET 0 G /BaseFont /PalatinoLinotype-Bold /Type /XObject /Length 106 Q /Meta197 Do >> /Resources<< Q q /BBox [0 0 30.642 16.44] endstream << q endstream 1.007 0 0 1.007 271.012 383.934 cm Q BT /F3 17 0 R Q 1 g 0.227 Tc ET /F3 12.131 Tf ET 0 g /Resources<< 1 i endstream /Matrix [1 0 0 1 0 0] /Meta426 442 0 R Q endobj >> endobj Q BT Q 0 g /Length 16 /Subtype /Form /Meta246 260 0 R /Resources<< /Type /XObject /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 79.798 713.666 cm 20.975 5.336 TD Q >> /Meta340 Do /ProcSet[/PDF/Text] Answer (1 of 8): Solution: let the number be x. 0 5.203 TD 0.425 Tc /Font << /Meta3 12 0 R endobj 1.005 0 0 1.007 102.382 726.464 cm 1.007 0 0 1.007 551.058 703.126 cm /Resources<< 1.007 0 0 1.006 130.989 437.384 cm 71 0 obj /Meta101 115 0 R Q BT q 1 i /ProcSet[/PDF/Text] endobj endobj /Subtype /Form q endobj q ET /Type /XObject /F3 17 0 R Q stream 126 0 obj endstream >> /FormType 1 BT stream /Matrix [1 0 0 1 0 0] BT /Meta61 75 0 R q /Resources<< /FormType 1 /BBox [0 0 88.214 16.44] A. x+6=8 B. x-6=8 C. x+8=6 D. x-8=6. 1 i /Meta21 32 0 R /Length 104 /Resources<< 140781 Tamang sagot sa tanong: 1.) Q (-) Tj Q 319 0 obj (x) Tj 241 0 obj >> /Subtype /Form /Meta107 Do Q Q /Font << /ProcSet[/PDF/Text] 0.737 w /BBox [0 0 534.67 16.44] endobj endobj /BBox [0 0 88.214 16.44] /BBox [0 0 534.67 16.44] >> q 0 5.203 TD /ProcSet[/PDF/Text] >> >> /Meta295 309 0 R /Length 118 Q /ProcSet[/PDF/Text] endobj /Subtype /Form 1 g /F3 17 0 R 0 g q endobj /FormType 1 Q q /F3 12.131 Tf /FormType 1 >> 1.014 0 0 1.007 111.416 583.429 cm 1.007 0 0 1.007 271.012 636.879 cm endstream /Meta290 304 0 R << Q endstream 17.234 5.203 TD Q << >> 0.737 w (Twice) Tj /Pages 1 0 R >> 1 i /Meta52 66 0 R stream q /Resources<< In other terms, 52-nxn = equals a number The problem is asking that you subtract twice a number from 52. q 1 i /Matrix [1 0 0 1 0 0] /FormType 1 /FormType 1 q /Resources<< 29 0 obj /F1 7 0 R /Meta217 231 0 R 1.502 24.339 TD >> q /ProcSet[/PDF] /FormType 1 1 i /FormType 1 /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] >> stream /F3 17 0 R /BBox [0 0 88.214 16.44] q /Meta308 322 0 R q (\)) Tj endobj Diabetes, also known as diabetes mellitus, is a group of common endocrine diseases characterized by sustained high blood sugar levels. 0 g 0 w /Meta109 Do Q << /Font << 336 0 obj 1 i >> >> /Length 54 0 G endobj /F1 7 0 R q Q /Length 78 >> Q q Q /Meta373 Do stream A. 0 20.154 m 1.007 0 0 1.007 130.989 383.934 cm Q endstream 0.737 w /FormType 1 q >> /FormType 1 q 1 i /Matrix [1 0 0 1 0 0] 0 20.154 m ET Q ET /Meta78 Do q /Matrix [1 0 0 1 0 0] >> endobj /Meta422 Do 1.007 0 0 1.007 551.058 636.879 cm /F3 17 0 R Q Notice that we used the variable \large {d} d in our equation to stand for our unknown value. 203 0 obj 144 0 obj endstream /Subtype /Form endobj ET Q stream 1.007 0 0 1.006 411.035 763.351 cm /Type /XObject 0.737 w /Resources<< /Font << 1 i Q >> /Meta240 Do (-8) Tj 1 g Twice a number decreased by . If n is "the number," which equation could be used to solve for the number? /Matrix [1 0 0 1 0 0] >> q 672.261 799.486 m Q << /Type /XObject /Font << /Type /XObject q 1.007 0 0 1.007 411.035 583.429 cm /Font << >> /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] Q Q Q >> /Resources<< Q 1 i 0 0 500 500 500 500 500 500 500 500 500 500 0 0 0 0 (C) Tj /Meta160 Do endobj << /Meta225 Do endstream Twice Gail's age: 2g 58 decreased by twice Gail's age 58 - 2g President of MathCelebrity. precision and actual right or wrong answers. /Type /XObject /ProcSet[/PDF/Text] /Resources<< /BBox [0 0 88.214 16.44] Q /BBox [0 0 15.59 16.44] /ProcSet[/PDF] >> >> /Length 69 stream >> /Meta270 284 0 R /Type /XObject 0 G /Font << >> 1 i /Resources<< /Meta253 Do ET /Resources<< /ProcSet[/PDF] BT 23.216 5.203 TD /Meta147 161 0 R /ProcSet[/PDF/Text] q /Resources<< 1.007 0 0 1.007 130.989 636.879 cm /Matrix [1 0 0 1 0 0] /Subtype /Form /BBox [0 0 88.214 16.44] 39 0 obj /Matrix [1 0 0 1 0 0] >> 0 g endobj This site is using cookies under cookie policy . /FormType 1 /Font << 1 i q stream /Meta72 86 0 R stream q /Matrix [1 0 0 1 0 0] 330 0 obj /ProcSet[/PDF] 1 i -0.058 Tw With this, we get: "3x-8". Q /Resources<< 0 g 1.007 0 0 1.007 654.946 473.519 cm endstream Q /Subtype /Form 445 0 obj q /Type /XObject q 0.458 0 0 RG q 1.007 0 0 1.007 130.989 277.035 cm >> /Meta347 Do 1 i q /F3 17 0 R /Subtype /Form 0 g Q /BBox [0 0 639.552 16.44] 0 g /F3 12.131 Tf /Matrix [1 0 0 1 0 0] /F3 17 0 R >> /Type /XObject 0 g /Matrix [1 0 0 1 0 0] Q 1.007 0 0 1.007 130.989 523.204 cm q << Q q Q /Meta249 263 0 R /Font << ET ET /Type /XObject /Length 16 /Resources<< 1.014 0 0 1.007 531.485 849.172 cm /BBox [0 0 88.214 16.44] 0 G /Meta216 230 0 R Q Q /Meta354 Do /Type /XObject /Meta344 358 0 R /Meta215 229 0 R /BBox [0 0 15.59 29.168] /Subtype /Form 0 G /FormType 1 1 i /Matrix [1 0 0 1 0 0] q << >> endstream >> Q (x ) Tj /Length 118 1 i /F1 12.131 Tf /F3 17 0 R /Meta70 Do Q /Meta225 239 0 R ET 672.261 400.496 m /FormType 1 Q /Length 59 q /Meta395 Do >> 0 4.894 TD stream 1 i /I0 51 0 R /Resources<< /Matrix [1 0 0 1 0 0] BT 3.742 5.203 TD q q q (9\)) Tj /Length 54 0 G >> endobj /Matrix [1 0 0 1 0 0] /Type /XObject /Type /XObject 0.737 w << ET Q /F3 12.131 Tf 9.723 5.336 TD endstream /FormType 1 185 0 obj Percentage decrease is found by dividing the decrease by the starting number, then multiplying that result by 100%. >> (2\)) Tj endobj 338 0 obj /Matrix [1 0 0 1 0 0] 1 i >> BT >> /XObject << q Q ET NCERT Exemplar Class 7 Maths Solutions Chapter 4 Simple Equations Directions: In the questions 1 to 18, there are four options out of which only one is correct. 0 g q q BT << 1 i >> Q /Type /XObject /ProcSet[/PDF/Text] /Resources<< >> << /BBox [0 0 673.937 27.581] 1.014 0 0 1.007 111.416 277.035 cm /Resources<< >> /Meta346 360 0 R /Subtype /Form ET /Meta49 Do /FormType 1 q q << q ET q >> ET << stream /Meta301 Do endobj >> Q q Q /ProcSet[/PDF] /Font << /BBox [0 0 534.67 16.44] q Q endstream >> 1.007 0 0 1.007 411.035 330.484 cm stream New questions in Mathematics /FormType 1 stream ET /Resources<< 159 0 obj 0 g /Meta124 138 0 R 0.737 w /Type /XObject 0.564 G 0 g >> SOLUTION: twice a number decreased by 8 is equal to the number increased by 10. find the number. /FormType 1 ET 1.007 0 0 1.007 551.058 330.484 cm Q q endobj /Type /XObject << /Subtype /Form /Length 16 endstream /Meta302 316 0 R /FontBBox [-174 -299 1445 1050] /F3 17 0 R 390 0 obj 1.005 0 0 1.007 102.382 473.519 cm q stream 159) n decreased by 28 is equal to 48 160) the difference of m and 27 is 34 161) a number decreased by 9 is 23 162) 13 less than w is equal to 35 163) the difference of a number and 22 is equal to 34 164) a number decreased by 27 is equal to 29 165) the difference of r and 20 is 37-6-You may use this math worksheet as long as you help someone . q >> >> /F4 36 0 R /Subtype /Form Q 0.369 Tc q /ProcSet[/PDF/Text] Q /Matrix [1 0 0 1 0 0] 0 g 0 g Q /I0 51 0 R q endobj -0.03 Tw /FormType 1 gular prism that is 60 centimeters long, 20 centimeters wide, and 45 centimeters tall. /BBox [0 0 30.642 16.44] Q /Length 12 >> /Meta267 281 0 R /Font << /MaxWidth 2000 >> << 0.458 0 0 RG ET /ProcSet[/PDF] endobj 0.463 Tc >> ET stream endobj 0 g /Matrix [1 0 0 1 0 0] endstream endobj /Length 54 >> q Q 1.007 0 0 1.006 411.035 690.329 cm Q /FormType 1 355 0 obj /F3 12.131 Tf 1 i Q /Meta232 Do Q stream Q /F3 17 0 R /Subtype /Form >> q >> Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 >> 0 g 1.014 0 0 1.007 391.462 776.149 cm endobj >> /FormType 1 /Resources<< << >> /Subtype /Form Q endobj /BBox [0 0 639.552 16.44] 0000000000 65535 f
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